Conservative Forces:
If workdone by the force around a closed path is zero and it is independent of path then it is a conservative force. Under conservative force
\(F=-\frac{dU}{dx}\) where \(U\) is Potential Energy.
\(dU=-\int{\overline{F}}.\overline{dx}\)
Ex 1: Gravitational force is a conservative force
Ex 2: Electrostatic force betwen two stationary electric charges is a conservative force.
Ex 3: Magnetic force between two magnetic poles is a conservative force
Ex 4: Elastic force in a stretched spring is a conservative force
Non-Conservative Forces:
If the workdone by a force around a closed path is not equal to zero and it is dependent on the path then the force is non-conservative force
Ex:-Force of friction , Viscous force. Workdone by the non-conservative force will not be stored in the form of Potential energy.
Potential energy is undefined for a non conservative force.
Conceptual understanding
Ans: the change in potential energy of the system.
Ans: Work done is indepenent of the path (or)Work done in a closed loop is zero .
Ø When a body of mass m moves with a velocity ‘v’ its kinetic energy is \(KE=\frac{1}{2}m{{v}^{2}}\)
If two bodies of different masses have same velocity then \(KE\,\alpha \,m\)
ØAlso \(KE=\frac{1}{2}m{{v}^{2}}=\frac{{{m}^{2}}{{v}^{2}}}{2m}=\frac{{{\left( mv \right)}^{2}}}{2m}=\frac{{{p}^{2}}}{2m}\)
Ø If the two bodies of different masses have same momentum then lighter body will have greater
K.E \(\left( \because KE\alpha \frac{1}{m} \right)\)
ØWhen a bullet is fired from a gun the momentum of the bullet and gun are equal and opposite. It can be seen from the above expression that the ratio of kinetic energics of two bodies having the same
magnitude of momenta is in the inverse ratio of their masses \(i.e\,\,\,\,\frac{K\,bullet}{K\,gun}=\frac{M\,gun}{M\,bullet}\)
Hence, the KE of the bullet is greater than that of the gun
Ø A body can have energy without momentum. But it can not have momentum without energy.
ØA bullet of mass ‘m’ moving with velocity ‘v’ stops in wooden block aftger penterating through a distance x. If F is resistance offered by the block of the bullet (Assuming F is Constant inside the block)
\(\frac{1}{2}m{{v}^{2}}=Fx\)
\(F=\frac{m{{v}^{2}}}{2x}\)
\(\therefore \,{{v}^{2}}\alpha x\)
Conceptual understanding
1) For the same kinetic energy, the momentum shall be maximum for which of the following particle?
Ans:alpha particle
2) If the momentum of a particle is plotted on X-axis and its kinetic energy on the Y-axis, the graph is a
Ans: parabola
Illustrations:
Ans: 1 : 4 : 9
Ans: 1.2 J