MULTIPLICATION OF VECTORS BY REAL NUMBERS

MULTIPLICATION OF VECTORS BY REAL NUMBERS

Multiplying a vector A with a positive number \(\lambda\) gives a vector whose magnitude is changed by the factor \(\lambda\) but the direction is the same as that of A.

\(% MathType!MTEF!2!1!+- % feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaWaaqWaaeaacq % aH7oaBcaWGbbaacaGLhWUaayjcSdGaeyypa0Jaeq4UdW2aaqWaaeaa % caWGbbaacaGLhWUaayjcSdGaamyAaiaadAgacqaH7oaBcqGH+aGpca % aIWaaaaa!4783! \left| {\lambda A} \right| = \lambda \left| A \right|if\lambda > 0\)

For example, if A is multiplied by 2, the resultant vector 2A is in the same direction as A and has a magnitude twice of |A| as shown in Fig. 4.3(a). Multiplying a vector A by a negative number -\(\lambda\) gives another vector whose direction is opposite to the direction of A and whose magnitude is \(\lambda\) times |A|.

Multiplying a given vector A by negative numbers, say –1 and –1.5, gives vectors as shown in Fig 4.3(b).

                      fig. 4.3. (a) Vector A and the resultant vector after multiplying A by a positive number 2.​​​​​​​

                                   (b)Vector A and resultant vectors after multiplying it by a negative number –1 and –1.

The factor\(\lambda\) by which a vector A is multiplied could be a scalar having its own physical dimension. Then, the dimension of \(\lambda\) A is the product of the dimensions of \(\lambda\) and A. For example, if we multiply a constant velocity vector by duration (of time), we get a displacement vector.

ADDITION AND SUBTRACTION OF VECTORS-GRAPHICAL METHOD

ADDITION AND SUBTRACTION OF VECTORS-GRAPHICAL METHOD

As mentioned in section 4.2, vectors, by definition, obey the triangle law or equivalently, the parallelogram law of addition. We shall now describe this law of addition using the graphical method. Let us consider two vectors A and B that lie in a plane as shown in Fig. 4.4(a). The lengths of the line segments representing these vectors are proportional to the magnitude of the vectors. To find the sum A + B, we place vector B so that its tail is at the head of the vector A, as in Fig. 4.4(b).Then, we join the tail of A to the head of B. This line OQ represents a vector R, that is, the sum of the vectors A and B. Since, in this procedure of vector addition, vectors are

    fig  4.4 (a)Vectors A and B. (b) Vectors A and B added graphically.

    (c) Vectors B and A added graphically.

       (d) Illustrating the associative law of vector addition.

arranged head to tail, this graphical method is called the head-to-tail method. The two vectors and their resultant form three sides of a triangle, so this method is also known as triangle method of vector addition. If we find the resultant of B + A as in Fig. 4.4(c), the same vector R is obtained. Thus, vector addition is commutative:

                A + B = B + A(4.1)

The addition of vectors also obeys the associative law as illustrated in Fig. 4.4(d). The result of adding vectors A and B first and then adding vector C is the same as the result of adding B and C first and then adding vector A :

               (A + B) + C = A + (B + C)

What is the result of adding two equal and opposite vectors ? Consider two vectors A and –A shown in Fig. 4.3(b). Their sum is A + (–A). Since the magnitudes of the two vectors are the same, but the directions are opposite, the resultant vector has zero magnitude and is represented by 0 called a null vector or a zero vector :

A – A = 0        |0|= 0

Since the magnitude of a null vector is zero, its direction cannot be specified.

The null vector also results when we multiply a vector A by the number zero. The main properties of 0 are :

A + 0 = A

\(\lambda\) 0 = 0

0 A = 0 

What is the physical meaning of a zero vector? Consider the position and displacement vectors in a plane as shown in Fig. 4.1(a). Now suppose that an object which is at P at time t, moves to \(% MathType!MTEF!2!1!+- % feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGabmiuayaafa % aaaa!36D7! P'\) and then comes back to P. Then, what is its displacement? Since the initial and final positions coincide, the displacement is a “null vector”.

Subtraction of vectors can be defined in terms of addition of vectors. We define the difference of two vectors A and B as the sum of two vectors A and –B :

                          A – B = A + (–B)       

It is shown in Fig 4.5.The vector –B is added to vector A to get R₂ = (A – B). The vector R₁ = A + B is also shown in the same figure for comparison.We can also use the parallelogram method to find the sum of two vectors. Suppose we have two vectors A and B.To add these vectors, we bring their tails to a common origin O as shown in Fig. 4.6(a). Then we draw a line from the head of A parallel to B and another line from the head of B parallel to A to complete a parallelogram OQSP. Now we join the point of the intersection of these two lines to the origin

O.The resultant vector R is directed from the common origin O along the diagonal (OS) of the parallelogram [Fig. 4.6(b)]. In Fig.4.6(c), the triangle law is used to obtain the resultant of A and B and we see that the two methods yield the same result. Thus, the two methods are equivalent.

                   fig.4.5. (a)Two vectors A and B, – B is also shown.

                  (b) Subtracting vector B from vector A – the result is R₂.

                     For comparison, addition of  vectors A and B, i.e. R₁ is also shown.

EXAMPLE 1

Rain is falling vertically with a speed of 35 m s^–1. Winds starts blowing after sometime with a speed of 12 m s^–1 in east to west direction.In which direction should a boy waiting at a bus stop hold his umbrella ?

ANSWER

                    fig.4.7.

The velocity of the rain and the wind are represented by the vectors v_r and v_w in Fig.4.7.and are in the direction specified by the problem.Using the rule of vector addition,we see that the resultant of v_w is R as shown in figure.The magnitude of R is 

\(% MathType!MTEF!2!1!+- % feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaamOuaiabg2 % da9maakaaabaGaamODamaaDaaaleaacaWGYbaabaGaaGOmaaaakiab % gUcaRiaadAhadaqhaaWcbaGaam4Daaqaaiaaikdaaaaabeaakiabg2 % da9maakaaabaGaaG4maiaaiwdadaahaaWcbeqaaiaaikdaaaGccqGH % RaWkcaaIXaGaaGOmamaaCaaaleqabaGaaGOmaaaaaeqaaOGaamyBai % aadohadaahaaWcbeqaaiabgkHiTiaaigdaaaGccqGH9aqpcaaIZaGa % aG4naiaad2gacaWGZbWaaWbaaSqabeaacqGHsislcaaIXaaaaaaa!4F71! R = \sqrt {v_r^2 + v_w^2} = \sqrt {{{35}^2} + {{12}^2}} m{s^{ - 1}} = 37m{s^{ - 1}}\)

The direction \(\theta\) that R makes with the vertical is given by \(% MathType!MTEF!2!1!+- % feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn % hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr % 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9 % vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x % fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGcbaGaciiDaiaacg % gacaGGUbGaeqiUdeNaeyypa0ZaaSaaaeaacaWG2bWaaSbaaSqaaiaa % dEhaaeqaaaGcbaGaamODamaaBaaaleaacaWGYbaabeaaaaGccqGH9a % qpdaWcaaqaaiaaigdacaaIYaaabaGaaG4maiaaiwdaaaGaeyypa0Ja % aGimaiaac6cacaaIZaGaaGinaiaaiodaaaa!489B! \tan \theta = \frac{{{v_w}}}{{{v_r}}} = \frac{{12}}{{35}} = 0.343\)

=tan^-1(0.343)=19⁰tan

Therefore, the boy should hold his umbrella in the vertical plane at an angle of about 19^o with the vertical towards the east.