EXPERIMENT
Let us perform an activity using copper sulphate solution and iron nails to understand the chemical displacement reactions as follows
The equation is as follows
\(
CuSO_4 + Fe \to FeSO_4 + Cu
\)
Copper Sulphate + Iron \( \to \) Ferrous Sulphate + Copper
Activity: Experiment:
Apparatus:Beaker
Chemicals:Copper sulphate, a shining iron nail.
Procedure:Take copper sulphate powder in a beaker and add water so to make sulphate solution. Place the iron nail in the solution.Observe after sometime what happens in the beaker.
Observation: Red deposit is formed on the iron nail. The blue solution turns light green in colour.
Conclusion: The copper atom in copper sulphate molecule is displaced by iron atom and occupies its palce. So Ferrous sulphate is formed in the solution. So the original blue solution turns light green. The displaced copper form copper sulphate deposits on the iron nail. The deposit is red in colour.
Chemical Equation: Copper Sulphate + Iron \( \to \) Ferrous Sulphate + Copper
\(CuSO_4 + Fe \to FeSO_4 + Cu
\) (deposit)