Elimination of angle
Elimination of angle (\(\theta\)) by using trigonometric identities
The process of transforming trigonometric equation into an Algebric equation using trigonometric identities is called elimination of \(\theta\). Here ‘ \(\theta\) ‘ is an angle which is defined
Illustration -1 :
Eliminate ‘\(\theta\)‘ from the equations \(x = a\,\sin \theta ,\,\,y = a\cos \theta \Rightarrow \sin \theta = \frac{x}{a},\,\,\cos \theta = \frac{y}{a}\)
Solution :
We know \({\sin ^2}\theta + \cos {\theta ^2} = 1(\rlap{--} V\theta \in R)\)
\(\Rightarrow {\left( {\frac{x}{a}} \right)^2} + {\left( {\frac{y}{a}} \right)^2} = 1\)
\(\Rightarrow \frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{a^2}}} = 1\)
\(\Rightarrow {x^2} + {y^2} = {a^2}\)
Illustration -2 :
Eliminate ‘\(\theta
\)’ from the equation \(x = \sec \theta + \tan \theta ,\,\,\,y = \sec \theta - \tan \theta \).
Solution :
We know
\(\Rightarrow (\sec \theta + \tan \theta )(\sec \theta - \tan \theta ) = 1\) [(a+b)2 = a2 +b2 +2ab ]
\( \Rightarrow \,\,\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y\,\,\,\,\,\,\,\,\,\,\,\, = 1\)
\(\Rightarrow xy = 1\)
Illustration -3 :
Eliminate ‘\(\theta\)’ from the trigonometric equation \(a = x\cos \theta + y\sin \theta \) and \(b = x\sin \theta - y\cos \theta \)
Solution :
Squaring and adding the given equations
\(\left[ \begin{gathered}
\because {(a + b)^2} = {a^2} + {b^2} + 2ab \hfill \\
{(a - b)^2} = {a^2} + {b^2} - 2ab \hfill \\
\end{gathered} \right]\)
\({a^2} + {b^2} = {(x\cos \theta + y\sin \theta )^2} + {(x\sin \theta - y\cos \theta )^2}\)
\(= \,\,{x^2}({\sin ^2}\theta + {\cos ^2}\theta ) + {y^2}({\sin ^2}\theta + {\cos ^2}\theta ) + 2xy\sin \theta \cos \theta - \)\(2xy\sin \theta \cos \theta \) \(\left[ {\because {{\sin }^2}\theta \, + {{\cos }^2}\theta = 1} \right]\)
\(= {x^2}(1) + {y^2}(1)\)
\(= {x^2}(1) + {y^2}(1)\)
a2+b2=x2+y2