Equations of motion for a body projected vertically upwards
In case of a body projected vertically upwards a = -g
final velocity (v) = 0 at its highest point(maximum height). Therefore we get the equations of motion
(i) v=u+at => v=u-gt
(ii) \(
S = ut + \frac{1}
{2}at^2 \Rightarrow S = ut - \frac{1}
{2}gt^2
\) ( s is the distance travelled by the body in t sec)
(iii) \(
v^2 - u^2 = 2aS \Rightarrow v^2 - u^2 = 2( - g)S
\)
(iv) \(
S_n = u + a\left[ {n - \frac{1}
{2}} \right] \Rightarrow S_n = u - g\left[ {n - \frac{1}
{2}} \right]
\) (sn is the distance travelled in nth sec)