Chemical Reactions

EXPERIMENT
Let us perform an activity using Silver nitrate, Sodium chloride to understand the chemical double displacement reactions as follows-

Activity :Experiment:

Apparatus:Two test tubes.

Chemicals:Silver nitrate, Sodium chloride, Water.

Procedure: By taking a small qunatity of silver nitrate in a test - tube and adding sufficient water, prepare silver nitrate solution. Likewise prepare sodium chloride  solution by taking a small quantity of sodium chloride in another test -tube  and adding sufficient amount of water.Now add silver nitrate solution gradually to the  sodium chloride solution.

Observation: Formation of curd - like precipitate in the test - tube containing silver chloride is observed

Conclusion: Silver nitrate and Sodium chloride are two different compounds. During

chemical reaction, the constituents(ions) of the compounds get mutually exchanged. As a  result,silverchloride is formed as a precipitate and sodium nitrate as a solution.

Chemical  Equation:

        NaCl          +        AgNO₃         \( \to \)          AgCl            +        NaNO₃
    Sodium chloride  + Silver nitrate   \( \to \)      silverchloride  + sodium nitrate(aq)
              
After the completion of a double displacement reaction,one of the products is usually                 
1) a solid precipitate, 
2) a gas, or 
3) a molecular compound such as water.