DECIMALS
Savita and Shama were going to market to buy some stationary items. Savita said, “I have 5 rupees and 75 paise”. Shama said, “I have 7 rupees and 50 paise”. They knew how to write rupees and paise using decimals. So Savita said, I have Rs 5.75 and Shama said, “I have Rs 7.50”. Have they written correctly? We know that the dot represents a decimal point. In this chapter, we will learn more about working with decimals.
Ravi and Raju measured the lengths of their pencils. Ravi’s pencil was 7 cm 5mm long and Raju’s pencil was 8 cm 3 mm long. Can you express these lengths in centimetre using decimals?
We know that 10 mm = 1 cm
Therefore, 1 mm = \(\frac{1}{10}\) cm or one-tenth cm = 0.1
Now, length of Ravi’s pencil= 7cm 5mm
= \(7\frac{5}{10}\)cm i.e. 7cm and 5 tenths of a cm
= 7.5cm
The length of Raju’s pencil = 8 cm 3 mm
=\(8\frac{3}{10}\) cm i.e. 8 cm and 3 tenths of a cm
= 8.3 cm
Let us recall what we have learnt earlier. If we show units by blocks then one unit is one block, two units are two blocks and so on. One block divided into 10 equal parts means each part is \(\frac{1}{10}\) (one-tenth) of a unit, 2 parts show 2 tenths and 5 parts show 5 tenths and so on. A combination of 2 blocks and 3 parts (tenths) will be recorded as :
It can be written as 2.3 and read as two point three. Let us look at another example where we have more than ‘ones’. Each tower represents 10 units. So, the number shown here is :
i.e. 20 + 3 + \(\frac{5}{10}\) = 23.5
This is read as ‘twenty three point five’.
Try These
2. Write the length of Ravi’s and Raju’s pencil in ‘cm’ using decimals.
3. Make three more examples similar to the one given in question 1 and solve them.
We represented fractions on a number line. Let us now represent decimals too on a number line. Let us represent 0.6 on a number line.
We know that 0.6 is more than zero but less than one. There are 6 tenths in it. Divide the unit length between 0 and 1 into 10 equal parts and take 6 parts as shown below :
Write five numbers between 0 and 1 and show them on the number line.
Can you now represent 2.3 on a number line? Check, how many ones and tenths are there in 2.3. Where will it lie on the number line? Show 1.4 on the number line.
Example 1
Write the following numbers in the place value table : (a) 20.5 (b) 4.2
Solution
Let us make a common place value table, assigning appropriate place value to the digits in the given numbers. We have,
Example 2
Write each of the following as decimals : (a) Two ones and five-tenths (b) Thirty and one-tenth
Solution
(a) Two ones and five-tenths = 2 + \(\frac{5}{10}\) = 2.5
(b) Thirty and one-tenth = 30 + \(\frac{1}{10}\) = 30.1
Example 3
Write each of the following as decimals :
(a) 30 + 6 + \(\frac{2}{10}\) (b) 600 + 2 + \(\frac{8}{10}\)
Solution
(a) 30 + 6 + \(\frac{2}{10}\)
How many tens, ones and tenths are there in this number? We have 3 tens, 6 ones and 2 tenths.
Therefore, the decimal representation is 36.2.
(b) 600 + 2 + \(\frac{8}{10}\)
Note that it has 6 hundreds, no tens, 2 ones and 8 tenths.
Therefore, the decimal representation is 602.8
We have already seen how a fraction with denominator 10 can be represented using decimals.
Let us now try to find decimal representation of (a) \(\frac{11}{5}\) (b) \(\frac{1}{2}\)
We know that \(\frac{{11}}{5} = \frac{{22}}{{10}} = \frac{{20 + 2}}{{10}} = \frac{{20}}{{10}} + \frac{2}{{10}} = 2 + \frac{2}{{10}} = 2.2\)
Therefore, \(\frac{22}{10}\) = 2.2 (in decimal notation.)
(b) In \(\frac{1}{2}\) , the denominator is 2. For writing in decimal notation, the denominator should be 10. We already know how to make an equivalent fraction. So, \(\frac{1}{2} = \frac{{1 \times 5}}{{2 \times 5}} = \frac{5}{{10}} = 0.5\)
Try These
Till now we have learnt how to write fractions with denominators 10, 2 or 5 as decimals. Can we write a decimal number like 1.2 as a fraction? Let us see \(1.2 = 1 + \frac{2}{{10}} = \frac{{10}}{{10}} + \frac{2}{{10}} = \frac{2}{{10}}\)
E X E R C I S E 8.1
2. Write the following decimals in the place value table.
(a) 19.4 (b) 0.3 (c) 10.6 (d) 205.9
3. Write each of the following as decimals :
Write each of the following as decimals:
5.Write the following decimals as fractions. Reduce the fractions to lowest form.
6. Express the following as cm using decimals.
7. Between which two whole numbers on the number line are the given numbers lie?
Which of these whole numbers is nearer the number?
8. Show the following numbers on the number line.
(a) 0.2 (b) 1.9 (c) 1.1 (d) 2.5
9. Write the decimal number represented by the points A, B, C, D on the given number line
A =
B =
C =
D =
10. a) The length of Ramesh’s notebook is 9 cm 5 mm. What will be its length in cm?
b) The length of a young gram plant is 65 mm. Express its length in cm.
David was measuring the length of his room. He found that the length of his room is 4 m and 25 cm.
He wanted to write the length in metres.
Can you help him? What part of a metre will be one centimetre?
1 cm = \(\frac{1}{100}\) m or one-hundredth of a metre.
This means 25 cm = \(\frac{25}{100}\) m.
Now \(\frac{1}{100}\) means 1 part out of 100 parts of a whole. As we have done for \(\frac{1}{10}\) , let us try to show this pictorially.
Take a square and divide it into ten equal parts.
What part is the shaded rectangle of this square?
It is \(\frac{1}{10}\) or one-tenth or 0.1, see Fig (i).
Now divide each such rectangle into ten equal parts.
We get 100 small squares as shown in Fig (ii).
Then what fraction is each small square of the whole square?
Each small square is \(\frac{1}{100}\) or one-hundredth of the whole square. In decimal notation, we write \(\frac{1}{100}\) = 0.01 and read it as zero point zero one.
What part of the whole square is the shaded portion, if we shade 8 squares, 15 squares, 50 squares, 92 squares of the whole square? Take the help of following figures to answer.
Let us look at some more place value tables.
The number shown in the table above is \(2 + \frac{4}{{10}} + \frac{3}{{100}}\).In decimals, it is written as 2.43, which is read as ‘two point four three’.
Example 4
Fill the blanks in the table using ‘block’ information given below and write the corresponding number in decimal form.
Solution
The number is \(100 + 30 + 2 + \frac{1}{{10}} + \frac{5}{{100}} = 132.15\)
Example 5
Fill the blank in the table and write the corresponding number in decimal form using ‘block’ information given below.
Solution
Therefore, the number is 1.42.
Example 6
Given the place value table, write the number in decimal form.
Solution
The number is \(2 \times 100 + 4 \times 10 + 3 \times 1 + 2 \times \frac{1}{{10}} + 5 \times \left( {\frac{1}{{100}}} \right)\)
\( = 200 + 40 + 3 + \frac{1}{{10}} + \frac{5}{{100}} = 243.25\)
The first digit 2 is multiplied by 100; the next digit 4 is multiplied by 10 i.e. ( \(\frac{1}{10}\) of 100); the next digit 3 is multiplied by 1. After this, the next multiplying factor is \(\frac{1}{10}\) ; and then it is \(\frac{1}{100}\) i.e. ( \(\frac{1}{10}\) of \(\frac{1}{10}\) ).
The decimal point comes between ones place and tenths place in a decimal number. It is now natural to extend the place value table further, from hundredths to \(\frac{1}{10}\) of hundredths i.e. thousandths.
Let us solve some examples.
Example 7
Write as decimals. (a) \(\frac{4}{5}\) (b) \(\frac{3}{4}\) (c) \(\frac{7}{1000}\)
Solution
Example 8
Write as fractions in lowest terms.Solution
a) \(0.04 = \frac{4}{{100}} = \frac{1}{{25}}\)
b) \(2.34 = 2 + \frac{{34}}{{100}} = 2 + \frac{{34 \div 2}}{{100 \div 2}} = 2 + \frac{{17}}{{50}} = 2\frac{{17}}{{50}}\)
c) \(0.342 = \frac{{342}}{{1000}} = \frac{{342 \div 2}}{{1000 \div 2}} = \frac{{171}}{{500}}\)
Example 9
Write each of the following as a decimal.
a) \(200 + 30 + 5 + \frac{2}{{10}} + \frac{9}{{100}}\)
b) \(50 + \frac{1}{{10}} + \frac{6}{{100}}\)
c) \(16 + \frac{3}{{10}} + \frac{5}{{1000}} \)
Solution
a) \(200 + 30 + 5 + \frac{2}{{10}} + \frac{9}{{100}} = 235 + 2 \times \frac{1}{{10}} + 9 \times \frac{1}{{100}} = 235.29\)
b) \(50 + \frac{1}{{10}} + \frac{6}{{100}} = 50 + 1 \times \frac{1}{{10}} + 6 \times \frac{1}{{100}} = 50.16\)
c) \(16 + \frac{3}{{10}} + \frac{5}{{1000}} = 16 + \frac{3}{{10}} + \frac{0}{{100}} + \frac{5}{{1000}}\)
\( = 16 + 3 \times \frac{1}{{10}} + 0 \times \frac{1}{{100}} + 5 \times \frac{1}{{1000}} = 16.305\)
Example 10
Write each of the following as a decimal.
Solution
a. Three hundred six and seven-hundredths \( = 306 + \frac{7}{{100}} = 306 + 0 \times \frac{1}{{10}} + 7 \times \frac{1}{{100}} = 306.07\)
b. Eleven point two three five = 11.235
c. Nine and twenty five thousandths \( = 9 + \frac{{25}}{{1000}} = 9 + \frac{0}{{10}} + \frac{2}{{100}} + \frac{5}{{1000}} = 9.025\)
since, 25 thousands \( = \frac{{25}}{{1000}} = \frac{{20}}{{1000}} + \frac{5}{{1000}} = \frac{2}{{100}} + \frac{5}{{1000}}\)
E X E R C I S E 8.2
2. Write the numbers given in the following place value table in decimal form
3. Write the following decimals in the place value table.
5. Write each of the following decimals in words.
Can you tell which is greater, 0.07 or 0.1?
Take two pieces of square papers of the same size. Divide them into 100 equal parts. For 0.07 we have to shade 7 parts out of 100.
Now, 0.1 = \(\frac{1}{10}\) = \(\frac{1}{100}\) , so, for 0.1, shade 10 parts out 100.
This means 0.1>0.07
Let us now compare the numbers 32.55 and 32.5. In this case , we first compare the whole part. We see that the whole part for both the nunbers is 32 and, hence, equal.
We, however, know that the two numbers are not equal. So, we now compare the tenth part. We find that for 32.55 and 32.5, the tenth part is also equal, then we compare the hundredth part.
We find,
32.55 = 32 + \(\frac{5}{10}\) + \(\frac{5}{100}\) and 32.5 = 32 + \(\frac{5}{10}\) + \(\frac{5}{100}\) , therefore, 32.55>32.5 as the hundredth part of 32.55 is more.
Example 11
Which is greater?
(a) 1 or 0.99 (b) 1.09 or 1.093
Solution
a) \(1 = 1 + \frac{0}{{10}} + \frac{0}{{100}};0.99 = 0 + \frac{9}{{10}} + \frac{9}{{100}}\)
The whole part of 1 is greater than that of 0.99.
Therefore, 1 > 0.99
b) \(1.09 = 1 + \frac{0}{{10}} + \frac{9}{{100}} + \frac{0}{{1000}};1.093 = 1 + \frac{0}{{10}} + \frac{9}{{100}} + \frac{3}{{1000}}\)
In this case, the two numbers have same parts upto hundredth.
But the thousandths part of 1.093 is greater than that of 1.09.
Therefore, 1.093 > 1.09.
E X E R C I S E 8.3
We know that 100 paise = Re 1
Therefore, 1 paise = Re \(\frac{1}{100}\) = Re 0.01
So, 65 paise = Re \(\frac{65}{100}\) = Re 0.65
and 5 paise = Re \(\frac{5}{100}\) = Re 0.05
What is 105 paise? It is Re 1 and 5 paise = Rs 1.05
Try These
Mahesh wanted to measure the length of his table top in metres. He had a 50 cm scale. He found that the length of the table top was 156 cm. What will be its length in metres?
Mahesh knew that
1 cm = \(\frac{1}{100}\) m or 0.01 m
Therefore, 56 cm = \(\frac{56}{100}\) m = 0.56 m
Thus, the length of the table top is
156 cm = 100 cm + 56 cm
= 1 m + \(\frac{56}{100}\) m = 1.56 m.
Mahesh also wants to represent this length pictorially. He took squared papers of equal size and divided them into 100 equal parts.
He considered each small square as one cm.
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Nandu bought 500g potatoes, 250g capsicum, 700g onions, 500g tomatoes, 100g ginger and 300g radish. What is the total weight of the vegetables in the bag? Let us add the weight of all the vegetables in the bag.
500 g + 250 g + 700 g + 500 g + 100 g + 300 g = 2350 g
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We know that 1000 g = 1 kg
Therefore, 1 g = kg = 0.001 kg
Thus, 2350 g = 2000 g + 350 g
= \(\frac{2000}{1000}\) kg +\(\frac{350}{1000}\) kg
= 2 kg + 0.350 kg = 2.350 kg
i.e. 2350 g = 2 kg 350 g = 2.350 kg
Thus, the weight of vegetables in Nandu’s bag is 2.350 kg.
E X E R C I S E 8.4
Add 0.35 and 0.42.
Take a square and divide it into 100 equal parts.
Mark 0.35 in this square by shading 3 tenths and colouring 5 hundredths.
Mark 0.42 in this square by shading 4 tenths and colouring 2 hundredths.
Now count the total number of tenths in the square and the total number of hundredths in the square.
Therefore, 0.35 + 0.42 = 0.77
Thus, we can add decimals in the same way as whole numbers.
Can you now add 0.68 and 0.54?
Thus, 0.68 + 0.54 = 1.22
Try These
Example 12
Lata spent Rs 9.50 for buying a pen and Rs 2.50 for one pencil. How much money did she spend?
Solution
Money spent for pen = Rs 9.50
Money spent for pencil = Rs 2.50
Total money spent = Rs 9.50 + Rs 2.50
Total money spent = Rs 12.00
Example 13
Samson travelled 5 km 52 m by bus, 2 km 265 m by car and the rest 1km 30 m he walked. How much distance did he travel in all?
Solution
Distance travelled by bus = 5 km 52 m = 5.052 km
Distance travelled by car = 2 km 265 m = 2.265 km
Distance travelled on foot = 1 km 30 m = 1.030 km
Therefore, total distance travelled is
Therefore, total distance travelled = 8.347 km
Example 14
Rahul bought 4 kg 90 g of apples, 2 kg 60 g of grapes and 5 kg 300 g of mangoes. Find the total weight of all the fruits he bought.
Solution
Weight of apples = 4 kg 90 g = 4.090 kg
Weight of grapes = 2 kg 60 g = 2.060 kg
Weight of mangoes = 5 kg 300 g = 5.300 kg
Therefore, the total weight of the fruits bought is
Total weight of the fruits bought = 11.450 kg.
Subtract 1.32 from 2.58
This can be shown by the table.
Thus, 2.58 – 1.32 = 1.26
Therefore, we can say that, subtraction of decimals can be done by subtracting hundredths from hundredths, tenths from tenths, ones from ones and so on, just as we did in addition.
Sometimes while subtracting decimals, we may need to regroup like we did in addition.
Let us subtract 1.74 from 3.5.
Subtract in the hundredth place.
Can’t subtract !
so regroup
Thus, 3.5 – 1.74 = 1.76
Try These
Example 15
Abhishek had Rs 7.45. He bought toffees for Rs 5.30. Find the balance amount left with Abhishek.
Solution
Total amount of money = Rs 7.45
Amount spent on toffees = Rs 5.30
Balance amount of money = Rs 7.45 – Rs 5.30 = Rs 2.15
Example 16
Urmila’s school is at a distance of 5 km 350 m from her house. She travels 1 km 70 m on foot and the rest by bus. How much distance does she travel by bus?
Solution
Total distance of school from the house = 5.350 km
Distance travelled on foot = 1.070 km
Therefore, distance travelled by bus = 5.350 km – 1.070 km = 4.280 km
Thus, distance travelled by bus = 4.280 km or 4 km 280 m
Example 17
Kanchan bought a watermelon weighing 5 kg 200 g. Out of this she gave 2 kg 750 g to her neighbour. What is the weight of the watermelon left with Ruby?
Solution
Total weight of the watermelon = 5.200 kg
Watermelon given to the neighbour = 2.750 kg
Therefore, weight of the remaining watermelon
= 5.200 kg – 2.750 kg = 2.450 kg
E X E R C I S E 8.6
6. Namita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto? =
7. Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes and the rest is potatoes. What is the weight of the potatoes? =