ANGLES IN QUADRANTS
Behaviour of trigonometric Ratios \(\sin \theta ,\cos \theta ,\tan \theta \) as ‘\(\theta\) ‘ changes from o0 to 900 i.e., .\(0 \leqslant \theta \leqslant {90^0}\)
I) \(\theta\) For = 00
Let OP = r =1, if p (x, y) will co-incide with X-axis then op = r and x = 1, y = 0
\(sin{0^0} = \sin \theta = \frac{y}{r} = \frac{0}{1} = 0\,\,\,\,\, \Rightarrow \sin {0^0} = 0\)
\(\cos {0^0} = \cos \theta = \frac{x}{r} = \frac{1}{1} = 1\,\,\,\,\, \Rightarrow \cos {0^0} = 1\)
\(\tan {0^0} = \tan \theta = \frac{y}{x} = \frac{0}{1} = 0 \Rightarrow \tan {0^0} = 0\)
\(\csc {0^0} = \,\,\csc \theta \,\, = \,\,\frac{r}{y}\,\, = \,\,\,\,\frac{1}{0}\,\,\, = \,\,\,\infty \Rightarrow \csc {0^0} = \infty \)
\(\sec {0^0} = \sec \theta = \frac{r}{x} = \frac{1}{1} = 1 \Rightarrow \sec {0^0} = 1\)
\(\cot \theta = \frac{x}{y} = \frac{1}{0} = \infty \Rightarrow \cot {0^0} = \infty \)