MOTION OF BOAT IN A RIVER
1. Let \(\vec U\) be the velocity of boat in still water.is \(\vec V\) velocity of water in a river.If the boat moves in that river,its resultant velocity is \(
|\overrightarrow U + \overrightarrow V | = \sqrt {U^2 + V^2 + 2UV\cos \theta }
\) (Where \(\theta\) is the angle between U and V)
2. If the boat moves in down stream, \(
|\overrightarrow U + \overrightarrow V | =
\)U+V( \(\theta\)=00)
Time taken to cover a distance d is \(
t_1 = \frac{d}
{{(U + V)}}
\)
3. If the boat moves in up stream, \(
|\overrightarrow U + \overrightarrow V | =
\)U-V(\(\theta\) =1800)
Time taken to cover a distance d is \(
t_2 = \frac{d}
{{(U - V)}}
\)
4. From the above two conditions
\(
\frac{{t_1 }}
{{t_2 }} = \frac{{U - V}}
{{U + V}} \Rightarrow \frac{U}
{V} = \frac{{t_2 + t_1 }}
{{t_2 - t_1 }}
\)
5. If the boat moves at right angles to the stream, \(
|\overrightarrow U + \overrightarrow V | = \sqrt {U^2 + V^2 }
\)
6. To cross the river from one bank to the other in shortest time, boat should move at right angles to the stream (along AB)
7. Shortest time to cross the river t=d/U where d is width of the river Here boat suffers drift BC=x
x=Vt=\(
\left( {\frac{V}
{U}} \right)d
\)